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Examples

MoistAirTab™ Example 6 - Air Dehydration

Example 6

Ambient air at 85°F and 760 mm Hg and 55% relative humidity is compressed to 10 atm (gauge) to supply a requirement for 250 lb/hr of air (dry basis). The mixture is cooled in a condenser to remove 90% of the original moisture content. The air stream is further   dehydrated to -10°F dew point (at the line pressure) in a desiccant dryer. The pressure drop in condenser and desiccant dryer is 5 psi each. The isentropic efficiency of the air compressor is 85%.

  1. To what temperature must the air stream be cooled in the condenser?
  2. How much water needs to be removed in the desiccant dryer?

Solution

The solution is presented below as a table generated from Excel. The gray shaded areas represent the input data.

 

Solution: Units Ambient Air Compressor Outlet Condenser Outlet Desiccant Dryer Outlet
Flow rate (dry air) lbdry air/hr 250 250 250 250
Moisture removal %     90%  
Pressure mm Hg 760      
  atm   11    
  psia 14.69 161.59 156.59 151.59
Releative humidity % 55%   100%  
Dry bulb temperature °F 85   68.66  
Dew point temperature °F 67.04     -10
Humidity ratio lbw/lbdry air 0.0143 0.0143 0.0014 4.64949E-05
Moisture flow lbw/hr 3.568   0.357 0.012
Moisture removal lbw/hr     3.211 0.345